Storage Tank Engineering Curriculum
Module from the Storage Tank Engineering Curriculum curriculum.
Module 2 - Shell Thickness · Learning Objectives · 1. Apply 1-Foot Method: t_d = 2.6*D*(H-1)*G/(S_d*E) + CA (in) · 2. Apply Variable-Design Method for tanks > 200 ft diameter (more economical) · 3. Identify minimum nominal thickness by diameter (API 650 Table 5-6) · 4. Apply allowable stress per Table 5-2: S_d = 32/2.6 ksi for SA-516-70 · 5. Include corrosion allowance; typically 1/16 to 1/8 depending on service · API 650 Table 5-6 Minimum Shell Thickness
| Tank Diameter (ft) | Min Nominal Thk (in) | Notes | Size Class | Typical Use | Ref |
|---|---|---|---|---|---|
| <50 | 3/16 (0.1875) | Small tanks | Small | Small slop | API 650 |
| 50-120 | 1/4 (0.25) | Medium | Medium | Product | API 650 |
| 120-200 | 5/16 (0.3125) | Large | Large | Crude product | API 650 |
| >200 | 3/8 (0.375) | Very large | XL | Crude storage | API 650 |
| 1-Foot Method Formula and Example (120 ft D, 40 ft H, G=0.9, CA=1/16) | |||||
| Course 1 (bottom): t_d = 2.6 * 120 * (40-1) * 0.9 / (23200 * 1.0) + 0.0625 = 0.534 in. Round up to 9/16 (0.5625 in). Each higher course decreases H. Course 5 (H_liquid = 8 ft from top): t_d = 2.6 * 120 * (8-1) * 0.9 / (23200) + 0.0625 = 0.158 in - governed by Table 5-6 minimum 5/16 = 0.3125 in. |
Source: Storage_Tank_Engineering_Curriculum_v1.xlsx · Sheet: Shell Thk
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